3(s-5)=27

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Solution for 3(s-5)=27 equation: 



3(s-5)=27

We move all terms to the left:

3(s-5)-(27)=0

We multiply parentheses

3s-15-27=0

We add all the numbers together, and all the variables

3s-42=0

We move all terms containing s to the left, all other terms to the right

3s=42

s=42/3

s=14

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