3(s+2)=33

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Solution for 3(s+2)=33 equation: 



3(s+2)=33

We move all terms to the left:

3(s+2)-(33)=0

We multiply parentheses

3s+6-33=0

We add all the numbers together, and all the variables

3s-27=0

We move all terms containing s to the left, all other terms to the right

3s=27

s=27/3

s=9

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