3(s+1)-2(s-1)=10-(5-3s)

Solution for 3(s+1)-2(s-1)=10-(5-3s) equation:

3(s+1)-2(s-1)=10-(5-3s)

We move all terms to the left:

3(s+1)-2(s-1)-(10-(5-3s))=0

We add all the numbers together, and all the variables

3(s+1)-2(s-1)-(10-(-3s+5))=0

We multiply parentheses

3s-2s-(10-(-3s+5))+3+2=0


We calculate terms in parentheses: -(10-(-3s+5)), so:

10-(-3s+5)

determiningTheFunctionDomain
-(-3s+5)+10

We get rid of parentheses

3s-5+10

We add all the numbers together, and all the variables

3s+5

Back to the equation:

-(3s+5)


We add all the numbers together, and all the variables

s-(3s+5)+5=0

We get rid of parentheses

s-3s-5+5=0

We add all the numbers together, and all the variables

-2s=0

s=0/-2

s=0