3(r-6)+2=4(r+3)-21

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Solution for 3(r-6)+2=4(r+3)-21 equation: 



3(r-6)+2=4(r+3)-21

We move all terms to the left:

3(r-6)+2-(4(r+3)-21)=0

We multiply parentheses

3r-(4(r+3)-21)-18+2=0



We calculate terms in parentheses: -(4(r+3)-21), so:

4(r+3)-21

We multiply parentheses

4r+12-21

We add all the numbers together, and all the variables

4r-9

Back to the equation:

-(4r-9)



We add all the numbers together, and all the variables

3r-(4r-9)-16=0

We get rid of parentheses

3r-4r+9-16=0

We add all the numbers together, and all the variables

-1r-7=0

We move all terms containing r to the left, all other terms to the right

-r=7

r=7/-1

r=-7

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