3(r-6)+2=4(r+)-21

Solution for 3(r-6)+2=4(r+)-21 equation:

3(r-6)+2=4(r+)-21

We move all terms to the left:

3(r-6)+2-(4(r+)-21)=0

We add all the numbers together, and all the variables

3(r-6)-(4(+r)-21)+2=0

We multiply parentheses

3r-(4(+r)-21)-18+2=0


We calculate terms in parentheses: -(4(+r)-21), so:

4(+r)-21

We multiply parentheses

4r-21

Back to the equation:

-(4r-21)


We add all the numbers together, and all the variables

3r-(4r-21)-16=0

We get rid of parentheses

3r-4r+21-16=0

We add all the numbers together, and all the variables

-1r+5=0

We move all terms containing r to the left, all other terms to the right

-r=-5

r=-5/-1

r=+5