3(r-4)=7r-12-4r

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Solution for 3(r-4)=7r-12-4r equation:


Simplifying
3(r + -4) = 7r + -12 + -4r

Reorder the terms:
3(-4 + r) = 7r + -12 + -4r
(-4 * 3 + r * 3) = 7r + -12 + -4r
(-12 + 3r) = 7r + -12 + -4r

Reorder the terms:
-12 + 3r = -12 + 7r + -4r

Combine like terms: 7r + -4r = 3r
-12 + 3r = -12 + 3r

Add '12' to each side of the equation.
-12 + 12 + 3r = -12 + 12 + 3r

Combine like terms: -12 + 12 = 0
0 + 3r = -12 + 12 + 3r
3r = -12 + 12 + 3r

Combine like terms: -12 + 12 = 0
3r = 0 + 3r
3r = 3r

Add '-3r' to each side of the equation.
3r + -3r = 3r + -3r

Combine like terms: 3r + -3r = 0
0 = 3r + -3r

Combine like terms: 3r + -3r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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