3(r-2)-3(2-2r)=24

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Solution for 3(r-2)-3(2-2r)=24 equation: 



3(r-2)-3(2-2r)=24

We move all terms to the left:

3(r-2)-3(2-2r)-(24)=0

We add all the numbers together, and all the variables

3(r-2)-3(-2r+2)-24=0

We multiply parentheses

3r+6r-6-6-24=0

We add all the numbers together, and all the variables

9r-36=0

We move all terms containing r to the left, all other terms to the right

9r=36

r=36/9

r=4

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