3(r-10)+2(r-29)=2

Solution for 3(r-10)+2(r-29)=2 equation:

Simplifying
3(r + -10) + 2(r + -29) = 2

Reorder the terms:
3(-10 + r) + 2(r + -29) = 2
(-10 * 3 + r * 3) + 2(r + -29) = 2
(-30 + 3r) + 2(r + -29) = 2

Reorder the terms:
-30 + 3r + 2(-29 + r) = 2
-30 + 3r + (-29 * 2 + r * 2) = 2
-30 + 3r + (-58 + 2r) = 2

Reorder the terms:
-30 + -58 + 3r + 2r = 2

Combine like terms: -30 + -58 = -88
-88 + 3r + 2r = 2

Combine like terms: 3r + 2r = 5r
-88 + 5r = 2

Solving
-88 + 5r = 2

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '88' to each side of the equation.
-88 + 88 + 5r = 2 + 88

Combine like terms: -88 + 88 = 0
0 + 5r = 2 + 88
5r = 2 + 88

Combine like terms: 2 + 88 = 90
5r = 90

Divide each side by '5'.
r = 18

Simplifying
r = 18