3(r-1)+3(r+5)=(r-1)+18

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Solution for 3(r-1)+3(r+5)=(r-1)+18 equation:


3(r-1)+3(r+5)=(r-1)+18

We simplify the equation to the form, which is simple to understand 
3(r-1)+3(r+5)=(r-1)+18

Reorder the terms in parentheses
+(+3r-3)+3*(r+5)=(r-1)+18

Remove unnecessary parentheses
+3r-3+3+*(+r+5+)=+(+r-1+)+18

Reorder the terms in parentheses
+3r-3+(+3r+15)=(r-1)+18

Remove unnecessary parentheses
+3r-3+3r+15=+(+r-1+)+18

Remove unnecessary parentheses
+3r-3+3r+15=r-1+18

We move all terms containing r to the left and all other terms to the right. 
+3r+3r-1r=-1+18+3-15

We simplify left and right side of the equation. 
+5r=+5

We divide both sides of the equation by 5 to get r. 
r=1

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