3(r+4)=2(r-5)

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Solution for 3(r+4)=2(r-5) equation: 



3(r+4)=2(r-5)

We move all terms to the left:

3(r+4)-(2(r-5))=0

We multiply parentheses

3r-(2(r-5))+12=0



We calculate terms in parentheses: -(2(r-5)), so:

2(r-5)

We multiply parentheses

2r-10

Back to the equation:

-(2r-10)



We get rid of parentheses

3r-2r+10+12=0

We add all the numbers together, and all the variables

r+22=0

We move all terms containing r to the left, all other terms to the right

r=-22

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