3(r+4)-r=2r+12

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Solution for 3(r+4)-r=2r+12 equation:


Simplifying
3(r + 4) + -1r = 2r + 12

Reorder the terms:
3(4 + r) + -1r = 2r + 12
(4 * 3 + r * 3) + -1r = 2r + 12
(12 + 3r) + -1r = 2r + 12

Combine like terms: 3r + -1r = 2r
12 + 2r = 2r + 12

Reorder the terms:
12 + 2r = 12 + 2r

Add '-12' to each side of the equation.
12 + -12 + 2r = 12 + -12 + 2r

Combine like terms: 12 + -12 = 0
0 + 2r = 12 + -12 + 2r
2r = 12 + -12 + 2r

Combine like terms: 12 + -12 = 0
2r = 0 + 2r
2r = 2r

Add '-2r' to each side of the equation.
2r + -2r = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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