3(r+3)=5(r-3)+8

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Solution for 3(r+3)=5(r-3)+8 equation: 



3(r+3)=5(r-3)+8

We move all terms to the left:

3(r+3)-(5(r-3)+8)=0

We multiply parentheses

3r-(5(r-3)+8)+9=0



We calculate terms in parentheses: -(5(r-3)+8), so:

5(r-3)+8

We multiply parentheses

5r-15+8

We add all the numbers together, and all the variables

5r-7

Back to the equation:

-(5r-7)



We get rid of parentheses

3r-5r+7+9=0

We add all the numbers together, and all the variables

-2r+16=0

We move all terms containing r to the left, all other terms to the right

-2r=-16

r=-16/-2

r=+8

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