3(r+2)=5(2r-3)=r(3+2)+4r+3

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Solution for 3(r+2)=5(2r-3)=r(3+2)+4r+3 equation: 



3(r+2)=5(2r-3)=r(3+2)+4r+3

We move all terms to the left:

3(r+2)-(5(2r-3))=0

We multiply parentheses

3r-(5(2r-3))+6=0



We calculate terms in parentheses: -(5(2r-3)), so:

5(2r-3)

We multiply parentheses

10r-15

Back to the equation:

-(10r-15)



We get rid of parentheses

3r-10r+15+6=0

We add all the numbers together, and all the variables

-7r+21=0

We move all terms containing r to the left, all other terms to the right

-7r=-21

r=-21/-7

r=+3

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