3(r+2)-5(4-r)=12

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Solution for 3(r+2)-5(4-r)=12 equation:


Simplifying
3(r + 2) + -5(4 + -1r) = 12

Reorder the terms:
3(2 + r) + -5(4 + -1r) = 12
(2 * 3 + r * 3) + -5(4 + -1r) = 12
(6 + 3r) + -5(4 + -1r) = 12
6 + 3r + (4 * -5 + -1r * -5) = 12
6 + 3r + (-20 + 5r) = 12

Reorder the terms:
6 + -20 + 3r + 5r = 12

Combine like terms: 6 + -20 = -14
-14 + 3r + 5r = 12

Combine like terms: 3r + 5r = 8r
-14 + 8r = 12

Solving
-14 + 8r = 12

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 8r = 12 + 14

Combine like terms: -14 + 14 = 0
0 + 8r = 12 + 14
8r = 12 + 14

Combine like terms: 12 + 14 = 26
8r = 26

Divide each side by '8'.
r = 3.25

Simplifying
r = 3.25

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