3(r+1)+7(r+5)=338

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Solution for 3(r+1)+7(r+5)=338 equation:


Simplifying
3(r + 1) + 7(r + 5) = 338

Reorder the terms:
3(1 + r) + 7(r + 5) = 338
(1 * 3 + r * 3) + 7(r + 5) = 338
(3 + 3r) + 7(r + 5) = 338

Reorder the terms:
3 + 3r + 7(5 + r) = 338
3 + 3r + (5 * 7 + r * 7) = 338
3 + 3r + (35 + 7r) = 338

Reorder the terms:
3 + 35 + 3r + 7r = 338

Combine like terms: 3 + 35 = 38
38 + 3r + 7r = 338

Combine like terms: 3r + 7r = 10r
38 + 10r = 338

Solving
38 + 10r = 338

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-38' to each side of the equation.
38 + -38 + 10r = 338 + -38

Combine like terms: 38 + -38 = 0
0 + 10r = 338 + -38
10r = 338 + -38

Combine like terms: 338 + -38 = 300
10r = 300

Divide each side by '10'.
r = 30

Simplifying
r = 30

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