3(q-6)=18-q

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Solution for 3(q-6)=18-q equation: 



3(q-6)=18-q

We move all terms to the left:

3(q-6)-(18-q)=0

We add all the numbers together, and all the variables

3(q-6)-(-1q+18)=0

We multiply parentheses

3q-(-1q+18)-18=0

We get rid of parentheses

3q+1q-18-18=0

We add all the numbers together, and all the variables

4q-36=0

We move all terms containing q to the left, all other terms to the right

4q=36

q=36/4

q=9

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