3(q-5)=4a-(2a+4)

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Solution for 3(q-5)=4a-(2a+4) equation:


Simplifying
3(q + -5) = 4a + -1(2a + 4)

Reorder the terms:
3(-5 + q) = 4a + -1(2a + 4)
(-5 * 3 + q * 3) = 4a + -1(2a + 4)
(-15 + 3q) = 4a + -1(2a + 4)

Reorder the terms:
-15 + 3q = 4a + -1(4 + 2a)
-15 + 3q = 4a + (4 * -1 + 2a * -1)
-15 + 3q = 4a + (-4 + -2a)

Reorder the terms:
-15 + 3q = -4 + 4a + -2a

Combine like terms: 4a + -2a = 2a
-15 + 3q = -4 + 2a

Solving
-15 + 3q = -4 + 2a

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 3q = -4 + 15 + 2a

Combine like terms: -15 + 15 = 0
0 + 3q = -4 + 15 + 2a
3q = -4 + 15 + 2a

Combine like terms: -4 + 15 = 11
3q = 11 + 2a

Divide each side by '3'.
q = 3.666666667 + 0.6666666667a

Simplifying
q = 3.666666667 + 0.6666666667a

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