3(q-2)=3(q-12)

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Solution for 3(q-2)=3(q-12) equation: 



3(q-2)=3(q-12)

We move all terms to the left:

3(q-2)-(3(q-12))=0

We multiply parentheses

3q-(3(q-12))-6=0



We calculate terms in parentheses: -(3(q-12)), so:

3(q-12)

We multiply parentheses

3q-36

Back to the equation:

-(3q-36)



We get rid of parentheses

3q-3q+36-6=0

We add all the numbers together, and all the variables

30!=0

There is no solution for this equation

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