3(q-2)-2(2q+3)=8

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Solution for 3(q-2)-2(2q+3)=8 equation:



3(q-2)-2(2q+3)=8
We move all terms to the left:
3(q-2)-2(2q+3)-(8)=0
We multiply parentheses
3q-4q-6-6-8=0
We add all the numbers together, and all the variables
-1q-20=0
We move all terms containing q to the left, all other terms to the right
-q=20
q=20/-1
q=-20

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