3(q-2)+10=13

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Solution for 3(q-2)+10=13 equation: 



3(q-2)+10=13

We move all terms to the left:

3(q-2)+10-(13)=0

We add all the numbers together, and all the variables

3(q-2)-3=0

We multiply parentheses

3q-6-3=0

We add all the numbers together, and all the variables

3q-9=0

We move all terms containing q to the left, all other terms to the right

3q=9

q=9/3

q=3

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