3(q+-7)=27

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Solution for 3(q+-7)=27 equation: 



3(q+-7)=27

We move all terms to the left:

3(q+-7)-(27)=0

We add all the numbers together, and all the variables

3(q-7)-27=0

We multiply parentheses

3q-21-27=0

We add all the numbers together, and all the variables

3q-48=0

We move all terms containing q to the left, all other terms to the right

3q=48

q=48/3

q=16

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