3(p+2)=3(2p-4)+p

Solution for 3(p+2)=3(2p-4)+p equation:

3(p+2)=3(2p-4)+p

We move all terms to the left:

3(p+2)-(3(2p-4)+p)=0

We multiply parentheses

3p-(3(2p-4)+p)+6=0


We calculate terms in parentheses: -(3(2p-4)+p), so:

3(2p-4)+p

We add all the numbers together, and all the variables

p+3(2p-4)

We multiply parentheses

p+6p-12

We add all the numbers together, and all the variables

7p-12

Back to the equation:

-(7p-12)


We get rid of parentheses

3p-7p+12+6=0

We add all the numbers together, and all the variables

-4p+18=0

We move all terms containing p to the left, all other terms to the right

-4p=-18

p=-18/-4

p=4+1/2