3(p+2)=2(p-6)+p+18

Solution for 3(p+2)=2(p-6)+p+18 equation:

Simplifying
3(p + 2) = 2(p + -6) + p + 18

Reorder the terms:
3(2 + p) = 2(p + -6) + p + 18
(2 * 3 + p * 3) = 2(p + -6) + p + 18
(6 + 3p) = 2(p + -6) + p + 18

Reorder the terms:
6 + 3p = 2(-6 + p) + p + 18
6 + 3p = (-6 * 2 + p * 2) + p + 18
6 + 3p = (-12 + 2p) + p + 18

Reorder the terms:
6 + 3p = -12 + 18 + 2p + p

Combine like terms: -12 + 18 = 6
6 + 3p = 6 + 2p + p

Combine like terms: 2p + p = 3p
6 + 3p = 6 + 3p

Add '-6' to each side of the equation.
6 + -6 + 3p = 6 + -6 + 3p

Combine like terms: 6 + -6 = 0
0 + 3p = 6 + -6 + 3p
3p = 6 + -6 + 3p

Combine like terms: 6 + -6 = 0
3p = 0 + 3p
3p = 3p

Add '-3p' to each side of the equation.
3p + -3p = 3p + -3p

Combine like terms: 3p + -3p = 0
0 = 3p + -3p

Combine like terms: 3p + -3p = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.