3(p+1)-(4p-19)=4(p+1)-7

Solution for 3(p+1)-(4p-19)=4(p+1)-7 equation:

3(p+1)-(4p-19)=4(p+1)-7

We move all terms to the left:

3(p+1)-(4p-19)-(4(p+1)-7)=0

We multiply parentheses

3p-(4p-19)-(4(p+1)-7)+3=0

We get rid of parentheses

3p-4p-(4(p+1)-7)+19+3=0


We calculate terms in parentheses: -(4(p+1)-7), so:

4(p+1)-7

We multiply parentheses

4p+4-7

We add all the numbers together, and all the variables

4p-3

Back to the equation:

-(4p-3)


We add all the numbers together, and all the variables

-1p-(4p-3)+22=0

We get rid of parentheses

-1p-4p+3+22=0

We add all the numbers together, and all the variables

-5p+25=0

We move all terms containing p to the left, all other terms to the right

-5p=-25

p=-25/-5

p=+5