3(n-5)=41

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Solution for 3(n-5)=41 equation: 



3(n-5)=41

We move all terms to the left:

3(n-5)-(41)=0

We multiply parentheses

3n-15-41=0

We add all the numbers together, and all the variables

3n-56=0

We move all terms containing n to the left, all other terms to the right

3n=56

n=56/3

n=18+2/3

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