3(n-5)+3n=2-n

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Solution for 3(n-5)+3n=2-n equation: 



3(n-5)+3n=2-n

We move all terms to the left:

3(n-5)+3n-(2-n)=0

We add all the numbers together, and all the variables

3(n-5)+3n-(-1n+2)=0

We add all the numbers together, and all the variables

3n+3(n-5)-(-1n+2)=0

We multiply parentheses

3n+3n-(-1n+2)-15=0

We get rid of parentheses

3n+3n+1n-2-15=0

We add all the numbers together, and all the variables

7n-17=0

We move all terms containing n to the left, all other terms to the right

7n=17

n=17/7

n=2+3/7

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