3(n-4)=4(n-3)

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Solution for 3(n-4)=4(n-3) equation:


Simplifying
3(n + -4) = 4(n + -3)

Reorder the terms:
3(-4 + n) = 4(n + -3)
(-4 * 3 + n * 3) = 4(n + -3)
(-12 + 3n) = 4(n + -3)

Reorder the terms:
-12 + 3n = 4(-3 + n)
-12 + 3n = (-3 * 4 + n * 4)
-12 + 3n = (-12 + 4n)

Add '12' to each side of the equation.
-12 + 12 + 3n = -12 + 12 + 4n

Combine like terms: -12 + 12 = 0
0 + 3n = -12 + 12 + 4n
3n = -12 + 12 + 4n

Combine like terms: -12 + 12 = 0
3n = 0 + 4n
3n = 4n

Solving
3n = 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
3n + -4n = 4n + -4n

Combine like terms: 3n + -4n = -1n
-1n = 4n + -4n

Combine like terms: 4n + -4n = 0
-1n = 0

Divide each side by '-1'.
n = 0

Simplifying
n = 0

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