3(n-4)=3(n-2)-6

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Solution for 3(n-4)=3(n-2)-6 equation:


Simplifying
3(n + -4) = 3(n + -2) + -6

Reorder the terms:
3(-4 + n) = 3(n + -2) + -6
(-4 * 3 + n * 3) = 3(n + -2) + -6
(-12 + 3n) = 3(n + -2) + -6

Reorder the terms:
-12 + 3n = 3(-2 + n) + -6
-12 + 3n = (-2 * 3 + n * 3) + -6
-12 + 3n = (-6 + 3n) + -6

Reorder the terms:
-12 + 3n = -6 + -6 + 3n

Combine like terms: -6 + -6 = -12
-12 + 3n = -12 + 3n

Add '12' to each side of the equation.
-12 + 12 + 3n = -12 + 12 + 3n

Combine like terms: -12 + 12 = 0
0 + 3n = -12 + 12 + 3n
3n = -12 + 12 + 3n

Combine like terms: -12 + 12 = 0
3n = 0 + 3n
3n = 3n

Add '-3n' to each side of the equation.
3n + -3n = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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