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3(n-3)=2(n2)
We move all terms to the left:
3(n-3)-(2(n2))=0
determiningTheFunctionDomain 3(n-3)-2n2=0
We add all the numbers together, and all the variables
-2n^2+3(n-3)=0
We multiply parentheses
-2n^2+3n-9=0
a = -2; b = 3; c = -9;
Δ = b2-4ac
Δ = 32-4·(-2)·(-9)
Δ = -63
Delta is less than zero, so there is no solution for the equation
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