3(n-2)=3(n-5)+9

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Solution for 3(n-2)=3(n-5)+9 equation: 



3(n-2)=3(n-5)+9

We move all terms to the left:

3(n-2)-(3(n-5)+9)=0

We multiply parentheses

3n-(3(n-5)+9)-6=0



We calculate terms in parentheses: -(3(n-5)+9), so:

3(n-5)+9

We multiply parentheses

3n-15+9

We add all the numbers together, and all the variables

3n-6

Back to the equation:

-(3n-6)



We get rid of parentheses

3n-3n+6-6=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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