3(n-2)=2n+2(n-8)

Solution for 3(n-2)=2n+2(n-8) equation:

3(n-2)=2n+2(n-8)

We move all terms to the left:

3(n-2)-(2n+2(n-8))=0

We multiply parentheses

3n-(2n+2(n-8))-6=0


We calculate terms in parentheses: -(2n+2(n-8)), so:

2n+2(n-8)

We multiply parentheses

2n+2n-16

We add all the numbers together, and all the variables

4n-16

Back to the equation:

-(4n-16)


We get rid of parentheses

3n-4n+16-6=0

We add all the numbers together, and all the variables

-1n+10=0

We move all terms containing n to the left, all other terms to the right

-n=-10

n=-10/-1

n=+10