3(n-2)-(3-n)=4(n-3)

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Solution for 3(n-2)-(3-n)=4(n-3) equation: 



3(n-2)-(3-n)=4(n-3)

We move all terms to the left:

3(n-2)-(3-n)-(4(n-3))=0

We add all the numbers together, and all the variables

3(n-2)-(-1n+3)-(4(n-3))=0

We multiply parentheses

3n-(-1n+3)-(4(n-3))-6=0

We get rid of parentheses

3n+1n-(4(n-3))-3-6=0



We calculate terms in parentheses: -(4(n-3)), so:

4(n-3)

We multiply parentheses

4n-12

Back to the equation:

-(4n-12)



We add all the numbers together, and all the variables

4n-(4n-12)-9=0

We get rid of parentheses

4n-4n+12-9=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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