3(n-2)-(3-n)=3(n-4)

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Solution for 3(n-2)-(3-n)=3(n-4) equation:


Simplifying
3(n + -2) + -1(3 + -1n) = 3(n + -4)

Reorder the terms:
3(-2 + n) + -1(3 + -1n) = 3(n + -4)
(-2 * 3 + n * 3) + -1(3 + -1n) = 3(n + -4)
(-6 + 3n) + -1(3 + -1n) = 3(n + -4)
-6 + 3n + (3 * -1 + -1n * -1) = 3(n + -4)
-6 + 3n + (-3 + 1n) = 3(n + -4)

Reorder the terms:
-6 + -3 + 3n + 1n = 3(n + -4)

Combine like terms: -6 + -3 = -9
-9 + 3n + 1n = 3(n + -4)

Combine like terms: 3n + 1n = 4n
-9 + 4n = 3(n + -4)

Reorder the terms:
-9 + 4n = 3(-4 + n)
-9 + 4n = (-4 * 3 + n * 3)
-9 + 4n = (-12 + 3n)

Solving
-9 + 4n = -12 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
-9 + 4n + -3n = -12 + 3n + -3n

Combine like terms: 4n + -3n = 1n
-9 + 1n = -12 + 3n + -3n

Combine like terms: 3n + -3n = 0
-9 + 1n = -12 + 0
-9 + 1n = -12

Add '9' to each side of the equation.
-9 + 9 + 1n = -12 + 9

Combine like terms: -9 + 9 = 0
0 + 1n = -12 + 9
1n = -12 + 9

Combine like terms: -12 + 9 = -3
1n = -3

Divide each side by '1'.
n = -3

Simplifying
n = -3

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