3(n-2)+4(2n-5)=7

Solution for 3(n-2)+4(2n-5)=7 equation:

3(n-2)+4(2n-5)=7

We simplify the equation to the form, which is simple to understand 
3(n-2)+4(2n-5)=7

Reorder the terms in parentheses
+(+3n-6)+4*(2n-5)=7

Remove unnecessary parentheses
+3n-6+4+*(+2n-5+)=+7

Reorder the terms in parentheses
+3n-6+(+8n-20)=7

Remove unnecessary parentheses
+3n-6+8n-20=+7

We move all terms containing n to the left and all other terms to the right. 
+3n+8n=+7+6+20

We simplify left and right side of the equation. 
+11n=+33

We divide both sides of the equation by 11 to get n. 
n=3