3(n-12)=15+6(n-6)

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Solution for 3(n-12)=15+6(n-6) equation: 



3(n-12)=15+6(n-6)

We move all terms to the left:

3(n-12)-(15+6(n-6))=0

We multiply parentheses

3n-(15+6(n-6))-36=0



We calculate terms in parentheses: -(15+6(n-6)), so:

15+6(n-6)

determiningTheFunctionDomain
6(n-6)+15

We multiply parentheses

6n-36+15

We add all the numbers together, and all the variables

6n-21

Back to the equation:

-(6n-21)



We get rid of parentheses

3n-6n+21-36=0

We add all the numbers together, and all the variables

-3n-15=0

We move all terms containing n to the left, all other terms to the right

-3n=15

n=15/-3

n=-5

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