3(n-1)-2=4(n-4)-(n-11

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Solution for 3(n-1)-2=4(n-4)-(n-11 equation:



3(n-1)-2=4(n-4)-(n-11
We move all terms to the left:
3(n-1)-2-(4(n-4)-(n-11)=0
We multiply parentheses
3n-(4(n-4)-(n-11)-2-3=0

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