3(n-1)-2=4(n-4)-(n-1)

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Solution for 3(n-1)-2=4(n-4)-(n-1) equation:


3(n-1)-2=4(n-4)-(n-1)

We simplify the equation to the form, which is simple to understand
3(n-1)-2=4(n-4)-(n-1)

Reorder the terms in parentheses
+(+3n-3)-2=4*(n-4)-(n-1)

Remove unnecessary parentheses
+3n-3-2=+4+*(+n-4+)-(+n-1+)

Reorder the terms in parentheses
+3n-3-2=+(+4n-16)-(n-1)

Remove unnecessary parentheses
+3n-3-2=+4n-16-(+n-1+)

Remove unnecessary parentheses
+3n-3-2=+4n-16-1n+1

We move all terms containing n to the left and all other terms to the right.
+3n-4n+1n=-16+1+3+2

We simplify left and right side of the equation.
n=-10

0=-10

The left and right sides are not equal, therefore there is no solution. This equation is invalid.

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