3(n+n+2)+58=14(-n-4)

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Solution for 3(n+n+2)+58=14(-n-4) equation:


Simplifying
3(n + n + 2) + 58 = 14(-1n + -4)

Reorder the terms:
3(2 + n + n) + 58 = 14(-1n + -4)

Combine like terms: n + n = 2n
3(2 + 2n) + 58 = 14(-1n + -4)
(2 * 3 + 2n * 3) + 58 = 14(-1n + -4)
(6 + 6n) + 58 = 14(-1n + -4)

Reorder the terms:
6 + 58 + 6n = 14(-1n + -4)

Combine like terms: 6 + 58 = 64
64 + 6n = 14(-1n + -4)

Reorder the terms:
64 + 6n = 14(-4 + -1n)
64 + 6n = (-4 * 14 + -1n * 14)
64 + 6n = (-56 + -14n)

Solving
64 + 6n = -56 + -14n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '14n' to each side of the equation.
64 + 6n + 14n = -56 + -14n + 14n

Combine like terms: 6n + 14n = 20n
64 + 20n = -56 + -14n + 14n

Combine like terms: -14n + 14n = 0
64 + 20n = -56 + 0
64 + 20n = -56

Add '-64' to each side of the equation.
64 + -64 + 20n = -56 + -64

Combine like terms: 64 + -64 = 0
0 + 20n = -56 + -64
20n = -56 + -64

Combine like terms: -56 + -64 = -120
20n = -120

Divide each side by '20'.
n = -6

Simplifying
n = -6

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