3(n+5)=n+29

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Solution for 3(n+5)=n+29 equation: 



3(n+5)=n+29

We move all terms to the left:

3(n+5)-(n+29)=0

We multiply parentheses

3n-(n+29)+15=0

We get rid of parentheses

3n-n-29+15=0

We add all the numbers together, and all the variables

2n-14=0

We move all terms containing n to the left, all other terms to the right

2n=14

n=14/2

n=7

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