3(n+5)=7(n-3)

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Solution for 3(n+5)=7(n-3) equation: 



3(n+5)=7(n-3)

We move all terms to the left:

3(n+5)-(7(n-3))=0

We multiply parentheses

3n-(7(n-3))+15=0



We calculate terms in parentheses: -(7(n-3)), so:

7(n-3)

We multiply parentheses

7n-21

Back to the equation:

-(7n-21)



We get rid of parentheses

3n-7n+21+15=0

We add all the numbers together, and all the variables

-4n+36=0

We move all terms containing n to the left, all other terms to the right

-4n=-36

n=-36/-4

n=+9

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