3(n+5)=7(2n-1)

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Solution for 3(n+5)=7(2n-1) equation: 



3(n+5)=7(2n-1)

We move all terms to the left:

3(n+5)-(7(2n-1))=0

We multiply parentheses

3n-(7(2n-1))+15=0



We calculate terms in parentheses: -(7(2n-1)), so:

7(2n-1)

We multiply parentheses

14n-7

Back to the equation:

-(14n-7)



We get rid of parentheses

3n-14n+7+15=0

We add all the numbers together, and all the variables

-11n+22=0

We move all terms containing n to the left, all other terms to the right

-11n=-22

n=-22/-11

n=+2

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