3(n+5)=4(2n-5)

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Solution for 3(n+5)=4(2n-5) equation: 



3(n+5)=4(2n-5)

We move all terms to the left:

3(n+5)-(4(2n-5))=0

We multiply parentheses

3n-(4(2n-5))+15=0



We calculate terms in parentheses: -(4(2n-5)), so:

4(2n-5)

We multiply parentheses

8n-20

Back to the equation:

-(8n-20)



We get rid of parentheses

3n-8n+20+15=0

We add all the numbers together, and all the variables

-5n+35=0

We move all terms containing n to the left, all other terms to the right

-5n=-35

n=-35/-5

n=+7

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