3(n+5)+6=5(n+2)-5

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Solution for 3(n+5)+6=5(n+2)-5 equation: 



3(n+5)+6=5(n+2)-5

We move all terms to the left:

3(n+5)+6-(5(n+2)-5)=0

We multiply parentheses

3n-(5(n+2)-5)+15+6=0



We calculate terms in parentheses: -(5(n+2)-5), so:

5(n+2)-5

We multiply parentheses

5n+10-5

We add all the numbers together, and all the variables

5n+5

Back to the equation:

-(5n+5)



We add all the numbers together, and all the variables

3n-(5n+5)+21=0

We get rid of parentheses

3n-5n-5+21=0

We add all the numbers together, and all the variables

-2n+16=0

We move all terms containing n to the left, all other terms to the right

-2n=-16

n=-16/-2

n=+8

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