3(n+4)=n-36

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Solution for 3(n+4)=n-36 equation: 



3(n+4)=n-36

We move all terms to the left:

3(n+4)-(n-36)=0

We multiply parentheses

3n-(n-36)+12=0

We get rid of parentheses

3n-n+36+12=0

We add all the numbers together, and all the variables

2n+48=0

We move all terms containing n to the left, all other terms to the right

2n=-48

n=-48/2

n=-24

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