3(n+4)=3-3(n-5)

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Solution for 3(n+4)=3-3(n-5) equation:


Simplifying
3(n + 4) = 3 + -3(n + -5)

Reorder the terms:
3(4 + n) = 3 + -3(n + -5)
(4 * 3 + n * 3) = 3 + -3(n + -5)
(12 + 3n) = 3 + -3(n + -5)

Reorder the terms:
12 + 3n = 3 + -3(-5 + n)
12 + 3n = 3 + (-5 * -3 + n * -3)
12 + 3n = 3 + (15 + -3n)

Combine like terms: 3 + 15 = 18
12 + 3n = 18 + -3n

Solving
12 + 3n = 18 + -3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '3n' to each side of the equation.
12 + 3n + 3n = 18 + -3n + 3n

Combine like terms: 3n + 3n = 6n
12 + 6n = 18 + -3n + 3n

Combine like terms: -3n + 3n = 0
12 + 6n = 18 + 0
12 + 6n = 18

Add '-12' to each side of the equation.
12 + -12 + 6n = 18 + -12

Combine like terms: 12 + -12 = 0
0 + 6n = 18 + -12
6n = 18 + -12

Combine like terms: 18 + -12 = 6
6n = 6

Divide each side by '6'.
n = 1

Simplifying
n = 1

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