3(n+4)=28+7n

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Solution for 3(n+4)=28+7n equation: 



3(n+4)=28+7n

We move all terms to the left:

3(n+4)-(28+7n)=0

We add all the numbers together, and all the variables

3(n+4)-(7n+28)=0

We multiply parentheses

3n-(7n+28)+12=0

We get rid of parentheses

3n-7n-28+12=0

We add all the numbers together, and all the variables

-4n-16=0

We move all terms containing n to the left, all other terms to the right

-4n=16

n=16/-4

n=-4

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