3(n+4)=2(n+3)

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Solution for 3(n+4)=2(n+3) equation: 



3(n+4)=2(n+3)

We move all terms to the left:

3(n+4)-(2(n+3))=0

We multiply parentheses

3n-(2(n+3))+12=0



We calculate terms in parentheses: -(2(n+3)), so:

2(n+3)

We multiply parentheses

2n+6

Back to the equation:

-(2n+6)



We get rid of parentheses

3n-2n-6+12=0

We add all the numbers together, and all the variables

n+6=0

We move all terms containing n to the left, all other terms to the right

n=-6

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