3(n+4)=2(2n+3)

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Solution for 3(n+4)=2(2n+3) equation: 



3(n+4)=2(2n+3)

We move all terms to the left:

3(n+4)-(2(2n+3))=0

We multiply parentheses

3n-(2(2n+3))+12=0



We calculate terms in parentheses: -(2(2n+3)), so:

2(2n+3)

We multiply parentheses

4n+6

Back to the equation:

-(4n+6)



We get rid of parentheses

3n-4n-6+12=0

We add all the numbers together, and all the variables

-1n+6=0

We move all terms containing n to the left, all other terms to the right

-n=-6

n=-6/-1

n=+6

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