3(n+4)/5=11-(6-2n)/2

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Solution for 3(n+4)/5=11-(6-2n)/2 equation: 



3(n+4)/5=11-(6-2n)/2

We move all terms to the left:

3(n+4)/5-(11-(6-2n)/2)=0

We add all the numbers together, and all the variables

3(n+4)/5-(11-(-2n+6)/2)=0

We calculate fractions


3n/()+(-(11-(-2n+6)*5)/()=0



We calculate terms in parentheses: +(-(11-(-2n+6)*5)/(), so:

-(11-(-2n+6)*5)/(

We multiply all the terms by the denominator


-(11-(-2n+6)*5)



We calculate terms in parentheses: -(11-(-2n+6)*5), so:

11-(-2n+6)*5

determiningTheFunctionDomain
-(-2n+6)*5+11

We multiply parentheses

10n-30+11

We add all the numbers together, and all the variables

10n-19

Back to the equation:

-(10n-19)



We get rid of parentheses

-10n+19

Back to the equation:

+(-10n+19)



We get rid of parentheses

3n/()-10n+19=0

We multiply all the terms by the denominator


3n-10n*()+19*()=0

We add all the numbers together, and all the variables

3n-10n*()=0

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