3(n+4)+3=6(n+1)

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Solution for 3(n+4)+3=6(n+1) equation: 



3(n+4)+3=6(n+1)

We move all terms to the left:

3(n+4)+3-(6(n+1))=0

We multiply parentheses

3n-(6(n+1))+12+3=0



We calculate terms in parentheses: -(6(n+1)), so:

6(n+1)

We multiply parentheses

6n+6

Back to the equation:

-(6n+6)



We add all the numbers together, and all the variables

3n-(6n+6)+15=0

We get rid of parentheses

3n-6n-6+15=0

We add all the numbers together, and all the variables

-3n+9=0

We move all terms containing n to the left, all other terms to the right

-3n=-9

n=-9/-3

n=+3

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